Unit Circle Mechanics and Trigonometric Coordinates
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What is the equation of the unit circle centered at the origin?
$$x^2 + y^2 = 1$$ It has a radius \(r = 1\) centered at \((0, 0)\).
How is \(\tan\theta\) defined in terms of the unit circle coordinates \((x, y)\)?
$$\tan\theta = \frac{y}{x} = \frac{\sin\theta}{\cos\theta} \quad (x \neq 0)$$ \(\tan\theta\) represents the slope of the terminal ray.
How does the unit circle equation \(x^2 + y^2 = 1\) establish the Pythagorean trigonometric identity?
Substituting \(x = \cos\theta\) and \(y = \sin\theta\) into \(x^2 + y^2 = 1\) yields: $$\cos^2\theta + \sin^2\theta = 1$$
What is the reference angle \(\theta'\) (or \(\theta_r\)) for an angle \(\theta\) in standard position?
The acute positive angle formed between the terminal side of \(\theta\) and the horizontal \(x\)-axis. Reference angles always satisfy \(0 \le \theta' \le \frac{\pi}{2}\).
Find the reference angle for \(\theta = \frac{5\pi}{6}\).
Since \(\frac{5\pi}{6}\) is in Quadrant II: $$\theta' = \pi - \frac{5\pi}{6} = \frac{\pi}{6}$$
Find the reference angle for \(\theta = \frac{4\pi}{3}\).
Since \(\frac{4\pi}{3}\) is in Quadrant III: $$\theta' = \frac{4\pi}{3} - \pi = \frac{\pi}{3}$$
What mnemonic identifies which trigonometric functions are positive in Quadrants I through IV?
'All Students Take Calculus' (ASTC):
Quadrant I: All positive
Quadrant II: Sine positive
Quadrant III: Tangent positive
Quadrant IV: Cosine positive
What are the unit circle coordinates and trig values for \(\theta = 0\)?
Why are \(\tan\theta\) and \(\sec\theta\) undefined at \(\theta = \frac{\pi}{2}\) and \(\theta = \frac{3\pi}{2}\)?
Both have \(\cos\theta\) (or \(x\)) in the denominator: $$\tan\theta = \frac{y}{x}, \quad \sec\theta = \frac{1}{x}$$ At these angles, \(x = 0\), resulting in division by zero.
For a point \(P(x, y)\) where the terminal side of angle \(\theta\) intersects the unit circle, how are \(\cos\theta\) and \(\sin\theta\) defined?
$$x = \cos\theta$$ $$y = \sin\theta$$ Thus, any point on the unit circle has coordinates \((\cos\theta, \sin\theta)\).
How do you calculate the reference angle \(\theta'\) in each of Quadrants II, III, and IV (in radians)?