Unit Circle Mechanics and Trigonometric Coordinates

Core Concepts

Understand coordinates on the unit circle, circular definitions, signs, and reference angles.

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Unit Circle Mechanics and Trigonometric Coordinates

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What is the equation of the unit circle centered at the origin?
$$x^2 + y^2 = 1$$ It has a radius \(r = 1\) centered at \((0, 0)\).
How is \(\tan\theta\) defined in terms of the unit circle coordinates \((x, y)\)?
$$\tan\theta = \frac{y}{x} = \frac{\sin\theta}{\cos\theta} \quad (x \neq 0)$$ \(\tan\theta\) represents the slope of the terminal ray.
How does the unit circle equation \(x^2 + y^2 = 1\) establish the Pythagorean trigonometric identity?
Substituting \(x = \cos\theta\) and \(y = \sin\theta\) into \(x^2 + y^2 = 1\) yields: $$\cos^2\theta + \sin^2\theta = 1$$
What is the reference angle \(\theta'\) (or \(\theta_r\)) for an angle \(\theta\) in standard position?
Diagram of an angle theta in standard position terminating in quadrant two, showing its reference angle theta prime formed between the terminal ray and the negative x-axis on a coordinate plane with a circle centered at the origin.
The acute positive angle formed between the terminal side of \(\theta\) and the horizontal \(x\)-axis. Reference angles always satisfy \(0 \le \theta' \le \frac{\pi}{2}\).
Find the reference angle for \(\theta = \frac{5\pi}{6}\).
Since \(\frac{5\pi}{6}\) is in Quadrant II: $$\theta' = \pi - \frac{5\pi}{6} = \frac{\pi}{6}$$
Find the reference angle for \(\theta = \frac{4\pi}{3}\).
Since \(\frac{4\pi}{3}\) is in Quadrant III: $$\theta' = \frac{4\pi}{3} - \pi = \frac{\pi}{3}$$
What mnemonic identifies which trigonometric functions are positive in Quadrants I through IV?
A Cartesian plane illustrating the ASTC rule across four quadrants: Quadrant I has all positive, Quadrant II has sine positive, Quadrant III has tangent positive, and Quadrant IV has cosine positive.
'All Students Take Calculus' (ASTC): Quadrant I: All positive Quadrant II: Sine positive Quadrant III: Tangent positive Quadrant IV: Cosine positive
What are the unit circle coordinates and trig values for \(\theta = 0\)?
Coordinates: \((1, 0)\)\n$$\cos 0 = 1$$\n$$\sin 0 = 0$$\n$$\tan 0 = 0$$
What are the unit circle coordinates and trig values for \(\theta = \frac{\pi}{2}\)?
Coordinates: \((0, 1)\)\n$$\cos\frac{\pi}{2} = 0$$\n$$\sin\frac{\pi}{2} = 1$$\n$$\tan\frac{\pi}{2} = \text{undefined}$$
What are the unit circle coordinates and trig values for \(\theta = \pi\)?
Coordinates: \((-1, 0)\)\n$$\cos\pi = -1$$\n$$\sin\pi = 0$$\n$$\tan\pi = 0$$
What are the unit circle coordinates and trig values for \(\theta = \frac{3\pi}{2}\)?
Coordinates: \((0, -1)\)\n$$\cos\frac{3\pi}{2} = 0$$\n$$\sin\frac{3\pi}{2} = -1$$\n$$\tan\frac{3\pi}{2} = \text{undefined}$$
Why are \(\tan\theta\) and \(\sec\theta\) undefined at \(\theta = \frac{\pi}{2}\) and \(\theta = \frac{3\pi}{2}\)?
Both have \(\cos\theta\) (or \(x\)) in the denominator: $$\tan\theta = \frac{y}{x}, \quad \sec\theta = \frac{1}{x}$$ At these angles, \(x = 0\), resulting in division by zero.
For a point \(P(x, y)\) where the terminal side of angle \(\theta\) intersects the unit circle, how are \(\cos\theta\) and \(\sin\theta\) defined?
Unit circle on a coordinate grid showing a right triangle in the first quadrant, where an angle theta gives horizontal side cosine of theta, vertical side sine of theta, hypotenuse 1, and terminal point P with coordinates cosine of theta, sine of theta.
$$x = \cos\theta$$ $$y = \sin\theta$$ Thus, any point on the unit circle has coordinates \((\cos\theta, \sin\theta)\).
How do you calculate the reference angle \(\theta'\) in each of Quadrants II, III, and IV (in radians)?
A coordinate plane diagram illustrating formulas for finding the reference angle theta in Quadrants 2, 3, and 4 as pi minus theta, theta minus pi, and 2 pi minus theta, respectively, measured relative to the x-axis.
Quadrant II: $$\theta' = \pi - \theta$$ Quadrant III: $$\theta' = \theta - \pi$$ Quadrant IV: $$\theta' = 2\pi - \theta$$
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