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The Steps of Regrouping (Borrowing)
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When you regroup in subtraction, what exactly are you 'borrowing' from the tens place?
You are borrowing one ten, which is equal to \(10\) ones.
Step 1: 'Go next door.' Which place value is 'next door' to the ones place?
The tens place.
Step 2: After 'going next door' to the tens place, what happens to the digit there?
You cross it out and write the number that is one less. For example, a \(5\) becomes a \(4\).
Step 3: After borrowing from the tens, what happens to the digit in the ones place?
It increases by \(10\). You add the \(10\) you borrowed to the ones that are already there.
In the problem \(64 - 28\), you need to regroup. What does the \(6\) in the tens place become?
The \(6\) becomes a \(5\) because you borrowed one ten from it.
In the problem \(64 - 28\), after you regroup, what does the \(4\) in the ones place become?
The \(4\) becomes \(14\). (The original \(4\) ones plus the \(10\) ones you borrowed).
Let's regroup the number \(81\) to prepare for subtraction. What does it become?
The \(8\) in the tens place becomes a \(7\). The \(1\) in the ones place becomes an \(11\).
How do you regroup the number \(50\)?
The \(5\) in the tens place becomes a \(4\). The \(0\) in the ones place becomes a \(10\).
You have \(3\) dimes and \(2\) pennies (\(32¢\)). You need to pay for something that costs \(5¢\). How do you regroup your money?
You trade \(1\) dime for \(10\) pennies. Now you have \(2\) dimes and \(12\) pennies, and you can pay the \(5¢\).
After regrouping in the problem \(43 - 19\), what is the new subtraction problem in the ones column?
$$ 13 - 9 $$
After regrouping in the problem \(43 - 19\), what is the new subtraction problem in the tens column?
$$ 3 - 1 $$
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