Technique: Simplifying Trigonometric Expressions

Core Concepts

Apply reciprocal, quotient, and Pythagorean identities to simplify complex trigonometric expressions into their most basic forms. This stack focuses on the practical application of identities through algebraic manipulation and substitution.

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Technique: Simplifying Trigonometric Expressions

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Simplify the expression: $$ \sin(x) \cot(x) $$
Use the quotient identity \(\cot(x) = \frac{\cos(x)}{\sin(x)}\). $$ \sin(x) \cdot \frac{\cos(x)}{\sin(x)} = \cos(x) $$
Simplify: $$ \frac{\tan(\theta)}{\sec(\theta)} $$
Convert to \(\sin\) and \(\cos\): $$ \frac{\frac{\sin(\theta)}{\cos(\theta)}}{\frac{1}{\cos(\theta)}} = \frac{\sin(\theta)}{\cos(\theta)} \cdot \frac{\cos(\theta)}{1} = \sin(\theta) $$
Simplify the expression: $$ \cos^2(y) (1 + \tan^2(y)) $$
Use the Pythagorean identity \(1 + \tan^2(y) = \sec^2(y)\). The expression becomes: $$ \cos^2(y) \cdot \sec^2(y) = \cos^2(y) \cdot \frac{1}{\cos^2(y)} = 1 $$
Simplify: $$ \sec^2(\alpha) - 1 $$
Using the Pythagorean identity \(1 + \tan^2(\alpha) = \sec^2(\alpha)\), we can rearrange it to \(\tan^2(\alpha) = \sec^2(\alpha) - 1\). The simplified form is \(\tan^2(\alpha)\).
Simplify: $$ (1 - \sin^2(x))(\csc^2(x)) $$
Use the Pythagorean identity \(\cos^2(x) = 1 - \sin^2(x)\). The expression becomes: $$ \cos^2(x) \csc^2(x) = \cos^2(x) \cdot \frac{1}{\sin^2(x)} = \frac{\cos^2(x)}{\sin^2(x)} = \cot^2(x) $$
Simplify the expression: $$ \frac{\csc^2(x) - 1}{\cos^2(x)} $$
The numerator \(\csc^2(x) - 1 = \cot^2(x)\). The expression becomes: $$ \frac{\cot^2(x)}{\cos^2(x)} = \frac{\cos^2(x)/\sin^2(x)}{\cos^2(x)} = \frac{1}{\sin^2(x)} = \csc^2(x) $$
Simplify to a single trigonometric function: $$ \frac{\sin(x) + \tan(x)}{1 + \sec(x)} $$
Convert to \(\sin\) and \(\cos\): $$ \frac{\sin(x) + \frac{\sin(x)}{\cos(x)}}{1 + \frac{1}{\cos(x)}} = \frac{\frac{\sin(x)\cos(x) + \sin(x)}{\cos(x)}}{\frac{\cos(x) + 1}{\cos(x)}} = \frac{\sin(x)(\cos(x)+1)}{\cos(x)+1} = \sin(x) $$
Simplify the expression: $$ \cos(\theta)\csc(\theta) $$
Use the reciprocal identity \(\csc(\theta) = \frac{1}{\sin(\theta)}\). $$ \cos(\theta) \cdot \frac{1}{\sin(\theta)} = \frac{\cos(\theta)}{\sin(\theta)} = \cot(\theta) $$
Simplify: $$ \tan^2(x) - \sec^2(x) $$
The Pythagorean identity is \(1 + \tan^2(x) = \sec^2(x)\). Rearranging gives \(\tan^2(x) - \sec^2(x) = -1\). The answer is \(-1\).
Simplify: $$ \frac{1}{1+\sin(x)} + \frac{1}{1-\sin(x)} $$
Find a common denominator: $$ \frac{(1-\sin(x)) + (1+\sin(x))}{(1+\sin(x))(1-\sin(x))} = \frac{2}{1-\sin^2(x)} = \frac{2}{\cos^2(x)} = 2\sec^2(x) $$
Simplify: $$ (\sin(x)+\cos(x))^2 $$
Expand the expression: $$ \sin^2(x) + 2\sin(x)\cos(x) + \cos^2(x) $$ Group terms: $$ (\sin^2(x) + \cos^2(x)) + 2\sin(x)\cos(x) = 1 + 2\sin(x)\cos(x) $$
Simplify: $$ \frac{\sec^2(x)}{\tan(x)} - \tan(x) $$
Find a common denominator: $$ \frac{\sec^2(x) - \tan^2(x)}{\tan(x)} $$ Use Pythagorean identity \(\sec^2(x) - \tan^2(x) = 1\): $$ \frac{1}{\tan(x)} = \cot(x) $$
Simplify the expression \(\cos^3(x) + \sin^2(x)\cos(x)\).
Factor out \(\cos(x)\): $$ \cos(x) (\cos^2(x) + \sin^2(x)) $$ Apply the Pythagorean identity \(\cos^2(x) + \sin^2(x) = 1\): $$ \cos(x) \cdot 1 = \cos(x) $$
Simplify: $$ \frac{1-\cos^2(\theta)}{\sin(\theta)} $$
Use the Pythagorean identity \(1-\cos^2(\theta) = \sin^2(\theta)\): $$ \frac{\sin^2(\theta)}{\sin(\theta)} = \sin(\theta) $$
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