When using the standard algorithm, in which place value do you always begin multiplying?
You always start with the place value farthest to the right: the ones place.
For the problem \(231 \times 3\), what is the first step?
Multiply the ones digit of the top number by the bottom number: \(1 \times 3 = 3\). Write the \(3\) in the ones place of the answer.
For \(231 \times 3\), after multiplying the ones, what is the second step?
Multiply the tens digit by the bottom number: \(3 \times 3 = 9\). Write the \(9\) in the tens place of the answer.
For \(231 \times 3\), what is the final multiplication step?
Multiply the hundreds digit by the bottom number: \(2 \times 3 = 6\). Write the \(6\) in the hundreds place of the answer. The final product is \(693\).
Solve using the standard algorithm: $$ 423 \times 2 $$
"No regrouping" means that the product in each place value column is less than \(10\), so you do not have to carry any numbers over to the next column.
Solve using the standard algorithm: $$ 3,110 \times 3 $$