Addition Strategy: Near Doubles

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What is a 'near doubles' fact?
It's an addition problem where the two numbers are neighbors, meaning they are just one number apart (like \(4+5\) or \(6+7\)).
How can you use the doubles fact \(3+3=6\) to help you solve \(3+4\)?
You know \(3+3=6\). Since \(4\) is just one more than \(3\), the answer is one more than \(6\). So, \(3+4=7\).
Use a doubles fact to solve: \(4 + 5 = ?\)
Think: \(4+4=8\). Then add one more. So, \(4+5=9\).
Use a doubles fact to solve: \(5 + 6 = ?\)
Think: \(5+5=10\). Then add one more. So, \(5+6=11\).
Use a doubles fact to solve: \(6 + 7 = ?\)
Think: \(6+6=12\). Then add one more. So, \(6+7=13\).
Use a doubles fact to solve: \(7 + 8 = ?\)
Think: \(7+7=14\). Then add one more. So, \(7+8=15\).
Use a doubles fact to solve: \(8 + 9 = ?\)
Think: \(8+8=16\). Then add one more. So, \(8+9=17\).
Let's try another way. To solve \(4+5\), can you use \(5+5\)?
Yes. Think: \(5+5=10\). Since \(4\) is one less than \(5\), the answer is one less than \(10\). So, \(4+5=9\).
$$ 2 + 3 = ? $$
Think \(2+2=4\), so \(2+3=5\).
$$ 3 + 2 = ? $$
Think \(2+2=4\), so \(3+2=5\). (This is also a turn-around fact!)
$$ 8 + 7 = ? $$
Think \(7+7=14\), so \(8+7=15\).
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