Learn how to solve addition problems where the answer is more than 10, like 8+5. We'll use the 'Making Ten' strategy to break the problem into easier steps.
What does it mean to 'add across ten' or 'cross ten'?
It means you are solving an addition problem where the sum is greater than \(10\).
How can we use the 'Make a Ten' strategy to solve \(9+4\)?
First, make a ten: \(9+1=10\). You used \(1\) from the \(4\), so you have \(3\) left. Now add the leftover \(3\) to \(10\). \(10+3=13\). So, \(9+4=13\).
Let's solve \(8+5\). First, how much do you need to add to \(8\) to make \(10\)?
You need to add \(2\). (\(8+2=10\))
We are solving \(8+5\). We used \(2\) from the \(5\) to make \(10\). How much is left over from the \(5\)?
There is \(3\) left over, because \(5-2=3\).
Now for the last step to solve \(8+5\). We have our \(10\) and our leftover \(3\). What is the final answer?
You add \(10+3=13\). So, \(8+5=13\).
Use the 'Make a Ten' strategy to solve \(7+5\).
\(7+3=10\). There is \(2\) left from the \(5\). \(10+2=12\). So, \(7+5=12\).
Use the 'Make a Ten' strategy to solve \(6+8\).
\(6+4=10\). There is \(4\) left from the \(8\). \(10+4=14\). So, \(6+8=14\).
